Java’s BigDecimal class can handle arbitrary-precision signed decimal numbers. Let’s test your knowledge of them!

Given an array, s, of n real number strings, sort them in descending order — but wait, there’s more! Each number must be printed in the exact same format as it was read from stdin, meaning that **.1** is printed as **.1**, and **0.1** is printed as **0.1**. If two numbers represent numerically equivalent values (e.g.,.**1=0.1** ), then they must be listed in the same order as they were received as input).

Complete the code in the unlocked section of the editor below. You must rearrange array **s**‘s elements according to the instructions above.

**Input Format**

The first line consists of a single integer, n, denoting the number of integer strings.

Each line i of the n subsequent lines contains a real number denoting the value of **s-ith**.

**Constraints**

- Each s-ith has at most 300 digits.(so using BigDecimal)

**Output**

Reordering of array’s elements.

**Sample Input**

```
9
-100
50
0
56.6
90
0.12
.12
02.34
000.000
```

**Sample Output**

```
90
56.6
50
02.34
0.12
.12
0
000.000
-100
```

** Solution.java**

import java.math.BigDecimal; import java.util.*; class Solution{ public static void main(String []args){ Scanner sc=new Scanner(System.in); int n=sc.nextInt(); String[] s=new String[n+2]; //input for(int i=0;i<n;i++){ s[i]=sc.next(); } sc.close(); //sorting Arrays.sort(s,0,n,new Comparator<object>(){ public int compare(Object a1, Object a2) { BigDecimal bigDec1 = new BigDecimal((String)a1); BigDecimal bigDec2 = new BigDecimal((String)a2); return bigDec2.compareTo(bigDec1); } }); //output for(int i=0;i<n;i++){ System.out.println(s[i]); } } }

Thank You.

Arrays.sort(s,0,n,new Comparator()

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